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-10x^2-31x-15=0
a = -10; b = -31; c = -15;
Δ = b2-4ac
Δ = -312-4·(-10)·(-15)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-19}{2*-10}=\frac{12}{-20} =-3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+19}{2*-10}=\frac{50}{-20} =-2+1/2 $
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